G(x)=sqrt(x+1)

Lösung

G (x) = x + 1

x = \frac{1 + 1 + 4 G ^{2}}{2 G ^{2}}, x = \frac{1 - 1 + 4 G ^{2}}{2 G ^{2}} {G < 0 or G > 0}

Schritte zur Lösung

G (x) = x + 1

Quadriere beide Seiten:

G^{2} x^{2} = x + 1

G^{2} x^{2} = x + 1

Löse

G^{2} x^{2} = x + 1 : x = \frac{1 + 1 + 4 G ^{2}}{2 G ^{2}}, x = \frac{1 - 1 + 4 G ^{2}}{2 G ^{2}}

x = \frac{1 + 1 + 4 G ^{2}}{2 G ^{2}}, x = \frac{1 - 1 + 4 G ^{2}}{2 G ^{2}}

Überprüfe die Lösungen:

x = \frac{1 + 1 + 4 G ^{2}}{2 G ^{2}}

Wahr

, x = \frac{1 - 1 + 4 G ^{2}}{2 G ^{2}} {G < 0 or G > 0}

Die Lösungen sind

x = \frac{1 + 1 + 4 G ^{2}}{2 G ^{2}}, x = \frac{1 - 1 + 4 G ^{2}}{2 G ^{2}} {G < 0 or G > 0}

x - 2 = - x + 2

x + 3 x + 10 = 6

3 x^{3} + 3 x^{2} = x + 1

1.19 = \frac{d}{2}

10 + 24 k = 13 1 + k^{2}