vereinfachen (81x^{24}y^{-20})^{1/4}

Lösung

vereinfachen

(81 x^{24} y^{- 20})^{\frac{1}{4}}

\frac{3 x ^{6}}{y ^{5}}

Schritte zur Lösung

(81 x^{24} y^{- 20})^{\frac{1}{4}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(81 x^{24} y^{- 20})^{\frac{1}{4}} = 8 1^{\frac{1}{4}} (x^{24})^{\frac{1}{4}} (y^{- 20})^{\frac{1}{4}}

= 8 1^{\frac{1}{4}} (x^{24})^{\frac{1}{4}} (y^{- 20})^{\frac{1}{4}}

8 1^{\frac{1}{4}} = 3

= 3 (x^{24})^{\frac{1}{4}} (y^{- 20})^{\frac{1}{4}}

Vereinfache

(x^{24})^{\frac{1}{4}} : x^{6}

= 3 x^{6} (y^{- 20})^{\frac{1}{4}}

Vereinfache

(y^{- 20})^{\frac{1}{4}} : \frac{1}{y ^{5}}

= 3 x^{6} \frac{1}{y ^{5}}

Vereinfache

3 x^{6} \frac{1}{y ^{5}} : \frac{3 x ^{6}}{y ^{5}}

= \frac{3 x ^{6}}{y ^{5}}

f a c t or a^{2} - 3 a - 4

x^{2} - 8 x - 105 = - 10

\frac{3 x + 5}{3} = 9

s im pl i f y \frac{n ^{2} - n - 12}{n ^{2} - 4 n}

∣ 7 x - 5 ∣ + 3 \geq 9