What is the answer to 5x-3(4x-1)=7-2(7x+2) ?

The answer to 5x-3(4x-1)=7-2(7x+2) is x=0

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5x-3(4x-1)=7-2(7x+2)

5 x - 3 (4 x - 1) = 7 - 2 (7 x + 2)

x = 0

Solution steps

5 x - 3 (4 x - 1) = 7 - 2 (7 x + 2)

Expand

- 3 (4 x - 1) : - 12 x + 3

5 x - 12 x + 3 = 7 - 2 (7 x + 2)

Add similar elements:

5 x - 12 x = - 7 x

- 7 x + 3 = 7 - 2 (7 x + 2)

Expand

7 - 2 (7 x + 2) : - 14 x + 3

- 7 x + 3 = - 14 x + 3

Move

3

to the right side

- 7 x = - 14 x

Move

14 x

to the left side

7 x = 0

Divide both sides by

7

x = 0

- \frac{4}{3} x = 16

12 - (4 x - 18) = (36 + 4 x) + (18 - 6 x)

- 1.5 x = 6

y, x = 1 - y

y, 4 x + 2 y = 200

What is the answer to 5x-3(4x-1)=7-2(7x+2) ?
The answer to 5x-3(4x-1)=7-2(7x+2) is x=0
Solve for x: 5x-3(4x-1)=7-2(7x+2)
The solution is x=0