What is the answer to solvefor k,k3^{n+2}-3k3^{n+1}+2k3^n=3^n ?

The answer to solvefor k,k3^{n+2}-3k3^{n+1}+2k3^n=3^n is k= 1/2

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solvefor k,k3^{n+2}-3k3^{n+1}+2k3^n=3^n

solve for

k, k 3^{n + 2} - 3 k 3^{n + 1} + 2 k 3^{n} = 3^{n}

k = \frac{1}{2}

Decimal

k = 0.5

Solution steps

k \cdot 3^{n + 2} - 3 k \cdot 3^{n + 1} + 2 k \cdot 3^{n} = 3^{n}

Simplify

k \cdot 3^{n + 2} - 3 k \cdot 3^{n + 1} + 2 k \cdot 3^{n} : 2 \cdot 3^{n} k

2 \cdot 3^{n} k = 3^{n}

Divide both sides by

2 \cdot 3^{n}

k = \frac{1}{2}

y, 3 x + 2 y = - 8

y, 3 x + 2 y = 20

\frac{2 x}{4 + 4} = 1

4 x + 6 = 86

9 x - 3 = 3

What is the answer to solvefor k,k3^{n+2}-3k3^{n+1}+2k3^n=3^n ?
The answer to solvefor k,k3^{n+2}-3k3^{n+1}+2k3^n=3^n is k= 1/2