What is the answer to (x+4)/3+(2x-3)/4 =7 ?

The answer to (x+4)/3+(2x-3)/4 =7 is x= 77/10

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(x+4)/3+(2x-3)/4 =7

\frac{x + 4}{3} + \frac{2 x - 3}{4} = 7

x = \frac{77}{10}

Decimal

x = 7.7

Solution steps

\frac{x + 4}{3} + \frac{2 x - 3}{4} = 7

Multiply by LCM

4 (x + 4) + 3 (2 x - 3) = 84

Expand

4 (x + 4) + 3 (2 x - 3) : 10 x + 7

10 x + 7 = 84

Move

7

to the right side

10 x = 77

Divide both sides by

10

x = \frac{77}{10}

5 m + 3 = - 32

x^{2} + 5 x - 2 (x^{2} + 3) = - x^{2} - 3 x + 11

y, 2 x = 5 - 3 y

20 - x = - 1

x, 5 = x - 21 + q

What is the answer to (x+4)/3+(2x-3)/4 =7 ?
The answer to (x+4)/3+(2x-3)/4 =7 is x= 77/10
Solve for x: (x+4)/3+(2x-3)/4 =7
The solution is x= 77/10