What is the answer to 2x+3(x-2)=6(x-1)+x ?

The answer to 2x+3(x-2)=6(x-1)+x is x=0

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2x+3(x-2)=6(x-1)+x

2 x + 3 (x - 2) = 6 (x - 1) + x

x = 0

Solution steps

2 x + 3 (x - 2) = 6 (x - 1) + x

Expand

3 (x - 2) : 3 x - 6

2 x + 3 x - 6 = 6 (x - 1) + x

Add similar elements:

2 x + 3 x = 5 x

5 x - 6 = 6 (x - 1) + x

Expand

6 (x - 1) + x : 7 x - 6

5 x - 6 = 7 x - 6

Move

6

to the right side

5 x = 7 x

Move

7 x

to the left side

- 2 x = 0

Divide both sides by

- 2

x = 0

\frac{25 \cdot ( q - 8 )}{20} = q

10 = - 2 - \frac{x}{3}

y = 4 \cdot 2^{- 2}

y, 5 x - 3 y + 1 = 0

\frac{3}{9} = \frac{x}{6}

What is the answer to 2x+3(x-2)=6(x-1)+x ?
The answer to 2x+3(x-2)=6(x-1)+x is x=0
Solve for x: 2x+3(x-2)=6(x-1)+x
The solution is x=0