What are the solutions to the equation (-9+(x-3)^2)/(-4)=-4 ?

The solutions to the equation (-9+(x-3)^2)/(-4)=-4 are x=8,x=-2

Find the zeros of (-9+(x-3)^2)/(-4)=-4

The zeros of (-9+(x-3)^2)/(-4)=-4 are x=8,x=-2

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\frac{- 9 + ( x - 3 ) ^{2}}{- 4} = - 4

x = 8, x = - 2

Solution steps

\frac{- 9 + ( x - 3 ) ^{2}}{- 4} = - 4

Multiply both sides by

- 4

- 9 + (x - 3)^{2} = 16

Move

9

to the right side

(x - 3)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 25 : x = 8

Solve

x - 3 = - 25 : x = - 2

The solutions to the quadratic equation are:

x = 8, x = - 2

x^{2} - x - 2 = 0

x^{2} + 16 x + 63 = x + 7

x^{2} - 14 x + c

7 - x^{2} = 6

X^{2} - 7 X = 18

What are the solutions to the equation (-9+(x-3)^2)/(-4)=-4 ?
The solutions to the equation (-9+(x-3)^2)/(-4)=-4 are x=8,x=-2
Find the zeros of (-9+(x-3)^2)/(-4)=-4
The zeros of (-9+(x-3)^2)/(-4)=-4 are x=8,x=-2