What are the solutions to the equation (5x+7)^2-(-2x+5)^2=0 ?

The solutions to the equation (5x+7)^2-(-2x+5)^2=0 are x=-2/7 ,x=-4

Find the zeros of (5x+7)^2-(-2x+5)^2=0

The zeros of (5x+7)^2-(-2x+5)^2=0 are x=-2/7 ,x=-4

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(5 x + 7)^{2} - (- 2 x + 5)^{2} = 0

x = - \frac{2}{7}, x = - 4

Decimal

x = - 0.28571 \dots, x = - 4

Solution steps

(5 x + 7)^{2} - (- 2 x + 5)^{2} = 0

Expand

(5 x + 7)^{2} - (- 2 x + 5)^{2} : 21 x^{2} + 90 x + 24

21 x^{2} + 90 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 90 \pm 9 0 ^{2} - 4 \cdot 21 \cdot 24}{2 \cdot 21}

9 0^{2} - 4 \cdot 21 \cdot 24 = 78

x_{1, 2} = \frac{- 90 \pm 78}{2 \cdot 21}

Separate the solutions

x_{1} = \frac{- 90 + 78}{2 \cdot 21}, x_{2} = \frac{- 90 - 78}{2 \cdot 21}

x = \frac{- 90 + 78}{2 \cdot 21} : - \frac{2}{7}

x = \frac{- 90 - 78}{2 \cdot 21} : - 4

The solutions to the quadratic equation are:

x = - \frac{2}{7}, x = - 4

x^{2} + 20 x + c

y, 4 x^{2} - 16 x + 4 y^{2} + 16 = 0

x^{2} - 5 x + \frac{4}{9} = 0

2 (x + 4)^{2} + 15 = 17

x^{2} - 2 x - 2

What are the solutions to the equation (5x+7)^2-(-2x+5)^2=0 ?
The solutions to the equation (5x+7)^2-(-2x+5)^2=0 are x=-2/7 ,x=-4
Find the zeros of (5x+7)^2-(-2x+5)^2=0
The zeros of (5x+7)^2-(-2x+5)^2=0 are x=-2/7 ,x=-4