What are the solutions to the equation 2(x-7)^2-31=1 ?

The solutions to the equation 2(x-7)^2-31=1 are x=11,x=3

Find the zeros of 2(x-7)^2-31=1

The zeros of 2(x-7)^2-31=1 are x=11,x=3

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2 (x - 7)^{2} - 31 = 1

x = 11, x = 3

Solution steps

2 (x - 7)^{2} - 31 = 1

Move

31

to the right side

2 (x - 7)^{2} = 32

Divide both sides by

2

(x - 7)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = 16 : x = 11

Solve

x - 7 = - 16 : x = 3

The solutions to the quadratic equation are:

x = 11, x = 3

x^{2} + 61 = 8 x

x^{2} + x - 2

x^{2} - 6 x + 13

- 7 f^{2} + 11 f + 9 = 4 - 3 f

4 x^{2} + 61 = 36 x

What are the solutions to the equation 2(x-7)^2-31=1 ?
The solutions to the equation 2(x-7)^2-31=1 are x=11,x=3
Find the zeros of 2(x-7)^2-31=1
The zeros of 2(x-7)^2-31=1 are x=11,x=3