-z^2+z=0

解

- z^{2} + z = 0

z = 0, z = 1

解答ステップ

- z^{2} + z = 0

解くとthe二次式

z_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 0 = 1

z_{1, 2} = \frac{- 1 \pm 1}{2 ( - 1 )}

解を分離する

z_{1} = \frac{- 1 + 1}{2 ( - 1 )}, z_{2} = \frac{- 1 - 1}{2 ( - 1 )}

z = \frac{- 1 + 1}{2 ( - 1 )} : 0

z = \frac{- 1 - 1}{2 ( - 1 )} : 1

二次equationの解:

z = 0, z = 1