n^2-11n+28=0

解

n^{2} - 11 n + 28 = 0

n = 7, n = 4

解答ステップ

n^{2} - 11 n + 28 = 0

解くとthe二次式

n_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 28 = 3

n_{1, 2} = \frac{- ( - 11 ) \pm 3}{2 \cdot 1}

解を分離する

n_{1} = \frac{- ( - 11 ) + 3}{2 \cdot 1}, n_{2} = \frac{- ( - 11 ) - 3}{2 \cdot 1}

n = \frac{- ( - 11 ) + 3}{2 \cdot 1} : 7

n = \frac{- ( - 11 ) - 3}{2 \cdot 1} : 4

二次equationの解:

n = 7, n = 4