What are the solutions to the equation roots 3x^2-8x-16 ?

The solutions to the equation roots 3x^2-8x-16 are x=4,x=-4/3

Find the zeros of roots 3x^2-8x-16

The zeros of roots 3x^2-8x-16 are x=4,x=-4/3

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roots

3 x^{2} - 8 x - 16

x = 4, x = - \frac{4}{3}

Solution steps

3 x^{2} - 8 x - 16

The roots are the intercepts with the x-axis

(y = 0)

3 x^{2} - 8 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 (- 16) = 16

x_{1, 2} = \frac{- ( - 8 ) \pm 16}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 16}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 16}{2 \cdot 3}

x = \frac{- ( - 8 ) + 16}{2 \cdot 3} : 4

x = \frac{- ( - 8 ) - 16}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 4, x = - \frac{4}{3}

25 x^{2} - 196 = 0

4 (x + 2)^{2} + 13 = 29

y, x^{2} + y^{2} = x y

y, 3 x^{2} + 5 x^{2} y^{2} = 2 y

x^{2} + 2 x - 4 = - 4

What are the solutions to the equation roots 3x^2-8x-16 ?
The solutions to the equation roots 3x^2-8x-16 are x=4,x=-4/3
Find the zeros of roots 3x^2-8x-16
The zeros of roots 3x^2-8x-16 are x=4,x=-4/3