What are the solutions to the equation roots x^2+5x+4 ?

The solutions to the equation roots x^2+5x+4 are x=-1,x=-4

Find the zeros of roots x^2+5x+4

The zeros of roots x^2+5x+4 are x=-1,x=-4

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roots

x^{2} + 5 x + 4

x = - 1, x = - 4

Solution steps

x^{2} + 5 x + 4

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 \cdot 1}, x_{2} = \frac{- 5 - 3}{2 \cdot 1}

x = \frac{- 5 + 3}{2 \cdot 1} : - 1

x = \frac{- 5 - 3}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 1, x = - 4

x^{2} - 49

x^{2} + 2 x + 1 = 0

3 x^{2} - x - 5

4 x^{2} + 37 = - 20 x

x^{2} + x + 4

What are the solutions to the equation roots x^2+5x+4 ?
The solutions to the equation roots x^2+5x+4 are x=-1,x=-4
Find the zeros of roots x^2+5x+4
The zeros of roots x^2+5x+4 are x=-1,x=-4