What are the solutions to the equation solvefor x,12320=160x^2+640x ?

The solutions to the equation solvefor x,12320=160x^2+640x are x=7,x=-11

Find the zeros of solvefor x,12320=160x^2+640x

The zeros of solvefor x,12320=160x^2+640x are x=7,x=-11

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x, 12320 = 160 x^{2} + 640 x

x = 7, x = - 11

Solution steps

12320 = 160 x^{2} + 640 x

Switch sides

160 x^{2} + 640 x = 12320

Move

12320

to the left side

160 x^{2} + 640 x - 12320 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 640 \pm 64 0 ^{2} - 4 \cdot 160 ( - 12320 )}{2 \cdot 160}

64 0^{2} - 4 \cdot 160 (- 12320) = 2880

x_{1, 2} = \frac{- 640 \pm 2880}{2 \cdot 160}

Separate the solutions

x_{1} = \frac{- 640 + 2880}{2 \cdot 160}, x_{2} = \frac{- 640 - 2880}{2 \cdot 160}

x = \frac{- 640 + 2880}{2 \cdot 160} : 7

x = \frac{- 640 - 2880}{2 \cdot 160} : - 11

The solutions to the quadratic equation are:

x = 7, x = - 11

12 x^{2} - 13 x + 4 = 13 x^{2} - 5 x + 1

x^{2} + 5 x - 310 = 0

a^{2} - 8 a - 12 = 0

y, (x + y)^{3} = x^{3} + y^{3}

x^{2} + 28 x + c

What are the solutions to the equation solvefor x,12320=160x^2+640x ?
The solutions to the equation solvefor x,12320=160x^2+640x are x=7,x=-11
Find the zeros of solvefor x,12320=160x^2+640x
The zeros of solvefor x,12320=160x^2+640x are x=7,x=-11