What are the solutions to the equation 5x^2-291x-16=0 ?

The solutions to the equation 5x^2-291x-16=0 are x=(291+sqrt(85001))/(10),x=(291-sqrt(85001))/(10)

Find the zeros of 5x^2-291x-16=0

The zeros of 5x^2-291x-16=0 are x=(291+sqrt(85001))/(10),x=(291-sqrt(85001))/(10)

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5 x^{2} - 291 x - 16 = 0

x = \frac{291 + 85001}{10}, x = \frac{291 - 85001}{10}

Decimal

x = 58.25493 \dots, x = - 0.05493 \dots

Solution steps

5 x^{2} - 291 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 291 ) \pm ( - 291 ) ^{2} - 4 \cdot 5 ( - 16 )}{2 \cdot 5}

(- 291)^{2} - 4 \cdot 5 (- 16) = 85001

x_{1, 2} = \frac{- ( - 291 ) \pm 85001}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 291 ) + 85001}{2 \cdot 5}, x_{2} = \frac{- ( - 291 ) - 85001}{2 \cdot 5}

x = \frac{- ( - 291 ) + 85001}{2 \cdot 5} : \frac{291 + 85001}{10}

x = \frac{- ( - 291 ) - 85001}{2 \cdot 5} : \frac{291 - 85001}{10}

The solutions to the quadratic equation are:

x = \frac{291 + 85001}{10}, x = \frac{291 - 85001}{10}

2 (x + 7)^{2} + 27 = 41

2 (x^{2} - 9) + 1 = 1

3 x (x - 3) = 2 (x + 2)

2 x^{2} - 200 = 138

x^{2} - 8 x + 15 = 0

What are the solutions to the equation 5x^2-291x-16=0 ?
The solutions to the equation 5x^2-291x-16=0 are x=(291+sqrt(85001))/(10),x=(291-sqrt(85001))/(10)
Find the zeros of 5x^2-291x-16=0
The zeros of 5x^2-291x-16=0 are x=(291+sqrt(85001))/(10),x=(291-sqrt(85001))/(10)