What are the solutions to the equation x^2+2x-13=130 ?

The solutions to the equation x^2+2x-13=130 are x=11,x=-13

Find the zeros of x^2+2x-13=130

The zeros of x^2+2x-13=130 are x=11,x=-13

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x^{2} + 2 x - 13 = 130

x = 11, x = - 13

Solution steps

x^{2} + 2 x - 13 = 130

Move

130

to the left side

x^{2} + 2 x - 143 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 143 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 143) = 24

x_{1, 2} = \frac{- 2 \pm 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 24}{2 \cdot 1}, x_{2} = \frac{- 2 - 24}{2 \cdot 1}

x = \frac{- 2 + 24}{2 \cdot 1} : 11

x = \frac{- 2 - 24}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

x = 11, x = - 13

- 4 x^{2} - 24 x + 64 = 0

x^{2} - 11 x + 10 = 0

s^{2} - s + 4

x^{2} - 6 x + 9

25 x^{2} + 40 x - 9 = 0

What are the solutions to the equation x^2+2x-13=130 ?
The solutions to the equation x^2+2x-13=130 are x=11,x=-13
Find the zeros of x^2+2x-13=130
The zeros of x^2+2x-13=130 are x=11,x=-13