What are the solutions to the equation -7x=3-4x^2 ?

The solutions to the equation -7x=3-4x^2 are x=-(-7+sqrt(97))/8 ,x=(7+sqrt(97))/8

Find the zeros of -7x=3-4x^2

The zeros of -7x=3-4x^2 are x=-(-7+sqrt(97))/8 ,x=(7+sqrt(97))/8

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- 7 x = 3 - 4 x^{2}

x = - \frac{- 7 + 97}{8}, x = \frac{7 + 97}{8}

Decimal

x = - 0.35610 \dots, x = 2.10610 \dots

Solution steps

- 7 x = 3 - 4 x^{2}

Switch sides

3 - 4 x^{2} = - 7 x

Move

7 x

to the left side

3 - 4 x^{2} + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 4 ) \cdot 3}{2 ( - 4 )}

7^{2} - 4 (- 4) \cdot 3 = 97

x_{1, 2} = \frac{- 7 \pm 97}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 7 + 97}{2 ( - 4 )}, x_{2} = \frac{- 7 - 97}{2 ( - 4 )}

x = \frac{- 7 + 97}{2 ( - 4 )} : - \frac{- 7 + 97}{8}

x = \frac{- 7 - 97}{2 ( - 4 )} : \frac{7 + 97}{8}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 97}{8}, x = \frac{7 + 97}{8}

6 + 3 x^{2} = 18

s^{2} + 2 s + 4

100 = x^{2} - 28 x + 296

(- 2 x + 1) (- 2 x - 7) = 0

w^{2} + 7 w + 4 = 0

What are the solutions to the equation -7x=3-4x^2 ?
The solutions to the equation -7x=3-4x^2 are x=-(-7+sqrt(97))/8 ,x=(7+sqrt(97))/8
Find the zeros of -7x=3-4x^2
The zeros of -7x=3-4x^2 are x=-(-7+sqrt(97))/8 ,x=(7+sqrt(97))/8