What are the solutions to the equation a^2-8a+12=2 ?

The solutions to the equation a^2-8a+12=2 are a=4+sqrt(6),a=4-sqrt(6)

Find the zeros of a^2-8a+12=2

The zeros of a^2-8a+12=2 are a=4+sqrt(6),a=4-sqrt(6)

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a^{2} - 8 a + 12 = 2

a = 4 + 6, a = 4 - 6

Decimal

a = 6.44948 \dots, a = 1.55051 \dots

Solution steps

a^{2} - 8 a + 12 = 2

Move

2

to the left side

a^{2} - 8 a + 10 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 10 = 26

a_{1, 2} = \frac{- ( - 8 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 8 ) + 2 6}{2 \cdot 1}, a_{2} = \frac{- ( - 8 ) - 2 6}{2 \cdot 1}

a = \frac{- ( - 8 ) + 2 6}{2 \cdot 1} : 4 + 6

a = \frac{- ( - 8 ) - 2 6}{2 \cdot 1} : 4 - 6

The solutions to the quadratic equation are:

a = 4 + 6, a = 4 - 6

- 3 (x + 2)^{2} = 24

150 x^{2} + x = 0

x^{2} + 2 x + 17 = 0

4 x^{2} + 20 x = - 17

x^{2} - b x + 16

What are the solutions to the equation a^2-8a+12=2 ?
The solutions to the equation a^2-8a+12=2 are a=4+sqrt(6),a=4-sqrt(6)
Find the zeros of a^2-8a+12=2
The zeros of a^2-8a+12=2 are a=4+sqrt(6),a=4-sqrt(6)