What are the solutions to the equation 3x^2+180=-48x ?

The solutions to the equation 3x^2+180=-48x are x=-6,x=-10

Find the zeros of 3x^2+180=-48x

The zeros of 3x^2+180=-48x are x=-6,x=-10

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3 x^{2} + 180 = - 48 x

x = - 6, x = - 10

Solution steps

3 x^{2} + 180 = - 48 x

Move

48 x

to the left side

3 x^{2} + 180 + 48 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 48 x + 180 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 3 \cdot 180}{2 \cdot 3}

4 8^{2} - 4 \cdot 3 \cdot 180 = 12

x_{1, 2} = \frac{- 48 \pm 12}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 48 + 12}{2 \cdot 3}, x_{2} = \frac{- 48 - 12}{2 \cdot 3}

x = \frac{- 48 + 12}{2 \cdot 3} : - 6

x = \frac{- 48 - 12}{2 \cdot 3} : - 10

The solutions to the quadratic equation are:

x = - 6, x = - 10

2 x^{2} = - 20

x^{2} - 4 x

x^{2} + 6 x + 10

x^{2} + 6 x + 25

x^{2} + 4 x = 0

What are the solutions to the equation 3x^2+180=-48x ?
The solutions to the equation 3x^2+180=-48x are x=-6,x=-10
Find the zeros of 3x^2+180=-48x
The zeros of 3x^2+180=-48x are x=-6,x=-10