What are the solutions to the equation solvefor x,0=3m^2x^2+2mx-5 ?

The solutions to the equation solvefor x,0=3m^2x^2+2mx-5 are x= 1/m ,x=-5/(3m);\quad m\ne 0

Find the zeros of solvefor x,0=3m^2x^2+2mx-5

The zeros of solvefor x,0=3m^2x^2+2mx-5 are x= 1/m ,x=-5/(3m);\quad m\ne 0

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x, 0 = 3 m^{2} x^{2} + 2 m x - 5

x = \frac{1}{m}, x = - \frac{5}{3 m}; m \neq = 0

Solution steps

0 = 3 m^{2} x^{2} + 2 m x - 5

Switch sides

3 m^{2} x^{2} + 2 m x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 m \pm ( 2 m ) ^{2} - 4 \cdot 3 m ^{2} ( - 5 )}{2 \cdot 3 m ^{2}}

Simplify

(2 m)^{2} - 4 \cdot 3 m^{2} (- 5) : 8 m

x_{1, 2} = \frac{- 2 m \pm 8 m}{2 \cdot 3 m ^{2}}; m \neq = 0

Separate the solutions

x_{1} = \frac{- 2 m + 8 m}{2 \cdot 3 m ^{2}}, x_{2} = \frac{- 2 m - 8 m}{2 \cdot 3 m ^{2}}

x = \frac{- 2 m + 8 m}{2 \cdot 3 m ^{2}} : \frac{1}{m}

x = \frac{- 2 m - 8 m}{2 \cdot 3 m ^{2}} : - \frac{5}{3 m}

The solutions to the quadratic equation are:

x = \frac{1}{m}, x = - \frac{5}{3 m}; m \neq = 0

4 (x + 7)^{2} = 16

5 (x - 3)^{2} = - 225

16 x^{2} - 24 x - 25 = 0

y, x^{2} + y^{2} + 4 x - 2 y + 5 = 0

(- x - 5) (2 x + 4) = 0

What are the solutions to the equation solvefor x,0=3m^2x^2+2mx-5 ?
The solutions to the equation solvefor x,0=3m^2x^2+2mx-5 are x= 1/m ,x=-5/(3m);\quad m\ne 0
Find the zeros of solvefor x,0=3m^2x^2+2mx-5
The zeros of solvefor x,0=3m^2x^2+2mx-5 are x= 1/m ,x=-5/(3m);\quad m\ne 0