What are the solutions to the equation roots x^2-9x+c ?

The solutions to the equation roots x^2-9x+c are x=(9+sqrt(81-4c))/2 ,x=(9-sqrt(81-4c))/2

Find the zeros of roots x^2-9x+c

The zeros of roots x^2-9x+c are x=(9+sqrt(81-4c))/2 ,x=(9-sqrt(81-4c))/2

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roots

x^{2} - 9 x + c

x = \frac{9 + 81 - 4 c}{2}, x = \frac{9 - 81 - 4 c}{2}

Solution steps

x^{2} - 9 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 9 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

(- 9)^{2} - 4 \cdot 1 \cdot c : 81 - 4 c

x_{1, 2} = \frac{- ( - 9 ) \pm 81 - 4 c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 81 - 4 c}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 81 - 4 c}{2 \cdot 1}

x = \frac{- ( - 9 ) + 81 - 4 c}{2 \cdot 1} : \frac{9 + 81 - 4 c}{2}

x = \frac{- ( - 9 ) - 81 - 4 c}{2 \cdot 1} : \frac{9 - 81 - 4 c}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 81 - 4 c}{2}, x = \frac{9 - 81 - 4 c}{2}

180 = 0.05 s^{2} + 1.1 s

y, y^{4} = y^{2} - x^{2}

2 x^{2} - 5 x - 6

x^{2} + 5 x - 36 = 0

2 (x - 2)^{2} - 39 = - 31

What are the solutions to the equation roots x^2-9x+c ?
The solutions to the equation roots x^2-9x+c are x=(9+sqrt(81-4c))/2 ,x=(9-sqrt(81-4c))/2
Find the zeros of roots x^2-9x+c
The zeros of roots x^2-9x+c are x=(9+sqrt(81-4c))/2 ,x=(9-sqrt(81-4c))/2