What are the solutions to the equation 9b^2+12b+5=1 ?

The solutions to the equation 9b^2+12b+5=1 are b=-2/3

Find the zeros of 9b^2+12b+5=1

The zeros of 9b^2+12b+5=1 are b=-2/3

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Popular >

9 b^{2} + 12 b + 5 = 1

b = - \frac{2}{3}

Decimal

b = - 0.66666 \dots

Solution steps

9 b^{2} + 12 b + 5 = 1

Move

1

to the left side

9 b^{2} + 12 b + 4 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

1 2^{2} - 4 \cdot 9 \cdot 4 = 0

b_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 9}

b = \frac{- 12}{2 \cdot 9}

\frac{- 12}{2 \cdot 9} = - \frac{2}{3}

b = - \frac{2}{3}

The solution to the quadratic equation is:

b = - \frac{2}{3}

p^{2} + 3 = - 10

2 x^{2} + 20 x + 28

x^{2} - 14 = - 5

y, x^{2} - x y + y^{2} = 1

9 x^{2} - 30 x + 26 = 0

What are the solutions to the equation 9b^2+12b+5=1 ?
The solutions to the equation 9b^2+12b+5=1 are b=-2/3
Find the zeros of 9b^2+12b+5=1
The zeros of 9b^2+12b+5=1 are b=-2/3