What is the answer to solvefor f,f(x+2)=(x+2)^2+1 ?

The answer to solvefor f,f(x+2)=(x+2)^2+1 is f=(x^2+4x+5)/(x+2);\quad x\ne-2

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solvefor f,f(x+2)=(x+2)^2+1

solve for

f, f (x + 2) = (x + 2)^{2} + 1

f = \frac{x ^{2} + 4 x + 5}{x + 2}; x \neq = - 2

Solution steps

f (x + 2) = (x + 2)^{2} + 1

Divide both sides by

x + 2; x \neq = - 2

f = \frac{x ^{2} + 4 x + 5}{x + 2}; x \neq = - 2

3 x^{2} - 2 x + 5 = 10 x + 1

x^{2} + 36

x^{2} + 4 x

4 (x^{2} - 8) - 6 = - 2

x^{2} - 5 x + 4

What is the answer to solvefor f,f(x+2)=(x+2)^2+1 ?
The answer to solvefor f,f(x+2)=(x+2)^2+1 is f=(x^2+4x+5)/(x+2);\quad x\ne-2