What are the solutions to the equation y^2-8y-2=0 ?

The solutions to the equation y^2-8y-2=0 are y=4+3sqrt(2),y=4-3sqrt(2)

Find the zeros of y^2-8y-2=0

The zeros of y^2-8y-2=0 are y=4+3sqrt(2),y=4-3sqrt(2)

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y^{2} - 8 y - 2 = 0

y = 4 + 32, y = 4 - 32

Decimal

y = 8.24264 \dots, y = - 0.24264 \dots

Solution steps

y^{2} - 8 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 2) = 62

y_{1, 2} = \frac{- ( - 8 ) \pm 6 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 6 2}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 6 2}{2 \cdot 1}

y = \frac{- ( - 8 ) + 6 2}{2 \cdot 1} : 4 + 32

y = \frac{- ( - 8 ) - 6 2}{2 \cdot 1} : 4 - 32

The solutions to the quadratic equation are:

y = 4 + 32, y = 4 - 32

x, x^{2} - 3 y^{2} - 2 y + z^{2} - 4 z = - 5

2 c^{2} - 5 c - 14 = - 5

x^{2} - 6 x + 8 = 0

5 r^{2} + r - 2 = 0

- 7 x^{2} - 10 = - 12 x

What are the solutions to the equation y^2-8y-2=0 ?
The solutions to the equation y^2-8y-2=0 are y=4+3sqrt(2),y=4-3sqrt(2)
Find the zeros of y^2-8y-2=0
The zeros of y^2-8y-2=0 are y=4+3sqrt(2),y=4-3sqrt(2)