What are the solutions to the equation 5c^2+12c+4=0 ?

The solutions to the equation 5c^2+12c+4=0 are c=-2/5 ,c=-2

Find the zeros of 5c^2+12c+4=0

The zeros of 5c^2+12c+4=0 are c=-2/5 ,c=-2

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5 c^{2} + 12 c + 4 = 0

c = - \frac{2}{5}, c = - 2

Decimal

c = - 0.4, c = - 2

Solution steps

5 c^{2} + 12 c + 4 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

1 2^{2} - 4 \cdot 5 \cdot 4 = 8

c_{1, 2} = \frac{- 12 \pm 8}{2 \cdot 5}

Separate the solutions

c_{1} = \frac{- 12 + 8}{2 \cdot 5}, c_{2} = \frac{- 12 - 8}{2 \cdot 5}

c = \frac{- 12 + 8}{2 \cdot 5} : - \frac{2}{5}

c = \frac{- 12 - 8}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

c = - \frac{2}{5}, c = - 2

2 (x - 5)^{2} + 2 = 20

8 x^{2} = 72 x

(3 x - 2)^{2} = (x + 1)^{2}

y, x^{2} - 14 x y + y^{2} = 14

2 x^{2} + 12 x + 6

What are the solutions to the equation 5c^2+12c+4=0 ?
The solutions to the equation 5c^2+12c+4=0 are c=-2/5 ,c=-2
Find the zeros of 5c^2+12c+4=0
The zeros of 5c^2+12c+4=0 are c=-2/5 ,c=-2