What are the solutions to the equation -4x^2-16x+20=0 ?

The solutions to the equation -4x^2-16x+20=0 are x=-5,x=1

Find the zeros of -4x^2-16x+20=0

The zeros of -4x^2-16x+20=0 are x=-5,x=1

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- 4 x^{2} - 16 x + 20 = 0

x = - 5, x = 1

Solution steps

- 4 x^{2} - 16 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 4 ) \cdot 20}{2 ( - 4 )}

(- 16)^{2} - 4 (- 4) \cdot 20 = 24

x_{1, 2} = \frac{- ( - 16 ) \pm 24}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 24}{2 ( - 4 )}, x_{2} = \frac{- ( - 16 ) - 24}{2 ( - 4 )}

x = \frac{- ( - 16 ) + 24}{2 ( - 4 )} : - 5

x = \frac{- ( - 16 ) - 24}{2 ( - 4 )} : 1

The solutions to the quadratic equation are:

x = - 5, x = 1

x^{2} - x - 6 = 0

4 (x^{2} - 6) - 3 = 9

x^{2} - 7 x = 0

x^{2} - 10 x + 21 = 0

4 w^{2} - 24 w = 0

What are the solutions to the equation -4x^2-16x+20=0 ?
The solutions to the equation -4x^2-16x+20=0 are x=-5,x=1
Find the zeros of -4x^2-16x+20=0
The zeros of -4x^2-16x+20=0 are x=-5,x=1