What are the solutions to the equation 8q^2-26q+15=0 ?

The solutions to the equation 8q^2-26q+15=0 are q= 5/2 ,q= 3/4

Find the zeros of 8q^2-26q+15=0

The zeros of 8q^2-26q+15=0 are q= 5/2 ,q= 3/4

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8 q^{2} - 26 q + 15 = 0

q = \frac{5}{2}, q = \frac{3}{4}

Decimal

q = 2.5, q = 0.75

Solution steps

8 q^{2} - 26 q + 15 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 8 \cdot 15}{2 \cdot 8}

(- 26)^{2} - 4 \cdot 8 \cdot 15 = 14

q_{1, 2} = \frac{- ( - 26 ) \pm 14}{2 \cdot 8}

Separate the solutions

q_{1} = \frac{- ( - 26 ) + 14}{2 \cdot 8}, q_{2} = \frac{- ( - 26 ) - 14}{2 \cdot 8}

q = \frac{- ( - 26 ) + 14}{2 \cdot 8} : \frac{5}{2}

q = \frac{- ( - 26 ) - 14}{2 \cdot 8} : \frac{3}{4}

The solutions to the quadratic equation are:

q = \frac{5}{2}, q = \frac{3}{4}

x^{2} + 5 x - 24 = 0

2 x^{2} - x - 1 = 0

81 x^{2} - 6 = 30

x, t an x + x se c^{2} x = 0

15 x^{2} + 31 x = - 14

What are the solutions to the equation 8q^2-26q+15=0 ?
The solutions to the equation 8q^2-26q+15=0 are q= 5/2 ,q= 3/4
Find the zeros of 8q^2-26q+15=0
The zeros of 8q^2-26q+15=0 are q= 5/2 ,q= 3/4