What are the solutions to the equation roots x^2+2x+c ?

The solutions to the equation roots x^2+2x+c are x=-1+sqrt(-c+1),x=-sqrt(-c+1)-1

Find the zeros of roots x^2+2x+c

The zeros of roots x^2+2x+c are x=-1+sqrt(-c+1),x=-sqrt(-c+1)-1

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roots

x^{2} + 2 x + c

x = - 1 + - c + 1, x = - - c + 1 - 1

Solution steps

x^{2} + 2 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 2 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot c : 2 1 - c

x_{1, 2} = \frac{- 2 \pm 2 1 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 1 - c}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 1 - c}{2 \cdot 1}

x = \frac{- 2 + 2 1 - c}{2 \cdot 1} : - 1 + - c + 1

x = \frac{- 2 - 2 1 - c}{2 \cdot 1} : - - c + 1 - 1

The solutions to the quadratic equation are:

x = - 1 + - c + 1, x = - - c + 1 - 1

x^{2} - 9 = 3 x + 1

16 - 25 y^{2} = 0

3 x^{2} + 6 x - 29 = - 4

y, x^{2} y = y - 7

2 x^{2} - 7 x + 4

What are the solutions to the equation roots x^2+2x+c ?
The solutions to the equation roots x^2+2x+c are x=-1+sqrt(-c+1),x=-sqrt(-c+1)-1
Find the zeros of roots x^2+2x+c
The zeros of roots x^2+2x+c are x=-1+sqrt(-c+1),x=-sqrt(-c+1)-1