What are the solutions to the equation 200=-0.5x^2+30x-200 ?

The solutions to the equation 200=-0.5x^2+30x-200 are x=20,x=40

Find the zeros of 200=-0.5x^2+30x-200

The zeros of 200=-0.5x^2+30x-200 are x=20,x=40

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200 = - 0.5 x^{2} + 30 x - 200

x = 20, x = 40

Solution steps

200 = - 0.5 x^{2} + 30 x - 200

Multiply both sides by

10

2000 = - 5 x^{2} + 300 x - 2000

Switch sides

- 5 x^{2} + 300 x - 2000 = 2000

Move

2000

to the left side

- 5 x^{2} + 300 x - 4000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 300 \pm 30 0 ^{2} - 4 ( - 5 ) ( - 4000 )}{2 ( - 5 )}

30 0^{2} - 4 (- 5) (- 4000) = 100

x_{1, 2} = \frac{- 300 \pm 100}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 300 + 100}{2 ( - 5 )}, x_{2} = \frac{- 300 - 100}{2 ( - 5 )}

x = \frac{- 300 + 100}{2 ( - 5 )} : 20

x = \frac{- 300 - 100}{2 ( - 5 )} : 40

The solutions to the quadratic equation are:

x = 20, x = 40

4 (5 x - 7)^{2} - 40 = - 32

3 (2 x + 5)^{2} + 23 = 38

y, x^{2} y^{2} + x y = 6

6 q^{2} + 10 q + 25 = 5 q^{2}

2 W^{2} + W - 45 = 0

What are the solutions to the equation 200=-0.5x^2+30x-200 ?
The solutions to the equation 200=-0.5x^2+30x-200 are x=20,x=40
Find the zeros of 200=-0.5x^2+30x-200
The zeros of 200=-0.5x^2+30x-200 are x=20,x=40