What are the solutions to the equation 4x^2+1.2x=0 ?

The solutions to the equation 4x^2+1.2x=0 are x=0,x=-0.3

Find the zeros of 4x^2+1.2x=0

The zeros of 4x^2+1.2x=0 are x=0,x=-0.3

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4 x^{2} + 1.2 x = 0

x = 0, x = - 0.3

Solution steps

4 x^{2} + 1.2 x = 0

Factor

4 x^{2} + 1.2 x : x (4 x + 1.2)

x (4 x + 1.2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x + 1.2 = 0

Solve

4 x + 1.2 = 0 : x = - 0.3

The solutions to the quadratic equation are:

x = 0, x = - 0.3

x^{2} + 15 x + 50

12 x^{2} + 12 x + 9 = 0

5 y^{2} + 13 y + 6 = 0

5 (x - 4)^{2} = 30

x^{2} + 2 x + 321 = 0

What are the solutions to the equation 4x^2+1.2x=0 ?
The solutions to the equation 4x^2+1.2x=0 are x=0,x=-0.3
Find the zeros of 4x^2+1.2x=0
The zeros of 4x^2+1.2x=0 are x=0,x=-0.3