What are the solutions to the equation 81x^2+198x+121=0 ?

The solutions to the equation 81x^2+198x+121=0 are x=-11/9

Find the zeros of 81x^2+198x+121=0

The zeros of 81x^2+198x+121=0 are x=-11/9

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81 x^{2} + 198 x + 121 = 0

x = - \frac{11}{9}

Decimal

x = - 1.22222 \dots

Solution steps

81 x^{2} + 198 x + 121 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 198 \pm 19 8 ^{2} - 4 \cdot 81 \cdot 121}{2 \cdot 81}

19 8^{2} - 4 \cdot 81 \cdot 121 = 0

x_{1, 2} = \frac{- 198 \pm 0}{2 \cdot 81}

x = \frac{- 198}{2 \cdot 81}

\frac{- 198}{2 \cdot 81} = - \frac{11}{9}

x = - \frac{11}{9}

The solution to the quadratic equation is:

x = - \frac{11}{9}

v, F = \frac{m v ^{2}}{r ^{2}}

3 + x = x^{2} + 3 x

x^{2} + 2 x + 17

0 = x^{2} + 20 x - 60

b x^{2} - b = x - b^{2} x

What are the solutions to the equation 81x^2+198x+121=0 ?
The solutions to the equation 81x^2+198x+121=0 are x=-11/9
Find the zeros of 81x^2+198x+121=0
The zeros of 81x^2+198x+121=0 are x=-11/9