What are the solutions to the equation roots x^2-x+7 ?

The solutions to the equation roots x^2-x+7 are x= 1/2+i(3sqrt(3))/2 ,x= 1/2-i(3sqrt(3))/2

Find the zeros of roots x^2-x+7

The zeros of roots x^2-x+7 are x= 1/2+i(3sqrt(3))/2 ,x= 1/2-i(3sqrt(3))/2

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roots

x^{2} - x + 7

x = \frac{1}{2} + i \frac{3 3}{2}, x = \frac{1}{2} - i \frac{3 3}{2}

Solution steps

x^{2} - x + 7

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 7 : 33 i

x_{1, 2} = \frac{- ( - 1 ) \pm 3 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3 3 i}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3 3 i}{2 \cdot 1} : \frac{1}{2} + i \frac{3 3}{2}

x = \frac{- ( - 1 ) - 3 3 i}{2 \cdot 1} : \frac{1}{2} - i \frac{3 3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{3 3}{2}, x = \frac{1}{2} - i \frac{3 3}{2}

k^{2} - 15 k + 64 = 5

(x - 2)^{2} + 19 = 28

- x^{2} - 8 x = 20

- x^{2} - 3.5 = - 12.5

11 x^{2} - 22 x = - 11

What are the solutions to the equation roots x^2-x+7 ?
The solutions to the equation roots x^2-x+7 are x= 1/2+i(3sqrt(3))/2 ,x= 1/2-i(3sqrt(3))/2
Find the zeros of roots x^2-x+7
The zeros of roots x^2-x+7 are x= 1/2+i(3sqrt(3))/2 ,x= 1/2-i(3sqrt(3))/2