What are the solutions to the equation v^2+4v-17=v ?

The solutions to the equation v^2+4v-17=v are v=(-3+sqrt(77))/2 ,v=(-3-sqrt(77))/2

Find the zeros of v^2+4v-17=v

The zeros of v^2+4v-17=v are v=(-3+sqrt(77))/2 ,v=(-3-sqrt(77))/2

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v^{2} + 4 v - 17 = v

v = \frac{- 3 + 77}{2}, v = \frac{- 3 - 77}{2}

Decimal

v = 2.88748 \dots, v = - 5.88748 \dots

Solution steps

v^{2} + 4 v - 17 = v

Move

v

to the left side

v^{2} + 3 v - 17 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 17) = 77

v_{1, 2} = \frac{- 3 \pm 77}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 3 + 77}{2 \cdot 1}, v_{2} = \frac{- 3 - 77}{2 \cdot 1}

v = \frac{- 3 + 77}{2 \cdot 1} : \frac{- 3 + 77}{2}

v = \frac{- 3 - 77}{2 \cdot 1} : \frac{- 3 - 77}{2}

The solutions to the quadratic equation are:

v = \frac{- 3 + 77}{2}, v = \frac{- 3 - 77}{2}

4 x - 1 = x^{2}

x^{2} + 2 x = 0

2 x^{2} - 16 x + 38

m, 6 m^{2} - 8 m + 1 = 0

6 x^{2} - 5 x - 2 = - 6 x^{2}

What are the solutions to the equation v^2+4v-17=v ?
The solutions to the equation v^2+4v-17=v are v=(-3+sqrt(77))/2 ,v=(-3-sqrt(77))/2
Find the zeros of v^2+4v-17=v
The zeros of v^2+4v-17=v are v=(-3+sqrt(77))/2 ,v=(-3-sqrt(77))/2