What are the solutions to the equation (9x-15)^2-2(9x-15)+1=0 ?

The solutions to the equation (9x-15)^2-2(9x-15)+1=0 are x= 16/9

Find the zeros of (9x-15)^2-2(9x-15)+1=0

The zeros of (9x-15)^2-2(9x-15)+1=0 are x= 16/9

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(9 x - 15)^{2} - 2 (9 x - 15) + 1 = 0

x = \frac{16}{9}

Decimal

x = 1.77777 \dots

Solution steps

(9 x - 15)^{2} - 2 (9 x - 15) + 1 = 0

Expand

(9 x - 15)^{2} - 2 (9 x - 15) + 1 : 81 x^{2} - 288 x + 256

81 x^{2} - 288 x + 256 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 288 ) \pm ( - 288 ) ^{2} - 4 \cdot 81 \cdot 256}{2 \cdot 81}

(- 288)^{2} - 4 \cdot 81 \cdot 256 = 0

x_{1, 2} = \frac{- ( - 288 ) \pm 0}{2 \cdot 81}

x = \frac{- ( - 288 )}{2 \cdot 81}

\frac{- ( - 288 )}{2 \cdot 81} = \frac{16}{9}

x = \frac{16}{9}

The solution to the quadratic equation is:

x = \frac{16}{9}

x^{2} + x - 12 = 0

3 x^{2} + 5 x - 100 = 0

y, y^{2} + y - x^{2} - x = 0

(3 x + 8)^{2} + 21 = 47

x^{2} - 20 = - 8 x

What are the solutions to the equation (9x-15)^2-2(9x-15)+1=0 ?
The solutions to the equation (9x-15)^2-2(9x-15)+1=0 are x= 16/9
Find the zeros of (9x-15)^2-2(9x-15)+1=0
The zeros of (9x-15)^2-2(9x-15)+1=0 are x= 16/9