What are the solutions to the equation 6x^2-19x+15=0 ?

The solutions to the equation 6x^2-19x+15=0 are x= 5/3 ,x= 3/2

Find the zeros of 6x^2-19x+15=0

The zeros of 6x^2-19x+15=0 are x= 5/3 ,x= 3/2

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6 x^{2} - 19 x + 15 = 0

x = \frac{5}{3}, x = \frac{3}{2}

Decimal

x = 1.66666 \dots, x = 1.5

Solution steps

6 x^{2} - 19 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 6 \cdot 15}{2 \cdot 6}

(- 19)^{2} - 4 \cdot 6 \cdot 15 = 1

x_{1, 2} = \frac{- ( - 19 ) \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 1}{2 \cdot 6}, x_{2} = \frac{- ( - 19 ) - 1}{2 \cdot 6}

x = \frac{- ( - 19 ) + 1}{2 \cdot 6} : \frac{5}{3}

x = \frac{- ( - 19 ) - 1}{2 \cdot 6} : \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = \frac{3}{2}

2.75 x^{2} - 0.3 x - 0.0225 = 0

3 (3 x + 1)^{2} - 43 = - 13

4 x^{2} - 20 x = - 5

x, s in x + x cos x = 0

x^{2} - 6 x + 8

What are the solutions to the equation 6x^2-19x+15=0 ?
The solutions to the equation 6x^2-19x+15=0 are x= 5/3 ,x= 3/2
Find the zeros of 6x^2-19x+15=0
The zeros of 6x^2-19x+15=0 are x= 5/3 ,x= 3/2