What are the solutions to the equation 2x^2-26x=-3x^2-7x-18 ?

The solutions to the equation 2x^2-26x=-3x^2-7x-18 are x= 9/5 ,x=2

Find the zeros of 2x^2-26x=-3x^2-7x-18

The zeros of 2x^2-26x=-3x^2-7x-18 are x= 9/5 ,x=2

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2 x^{2} - 26 x = - 3 x^{2} - 7 x - 18

x = \frac{9}{5}, x = 2

Decimal

x = 1.8, x = 2

Solution steps

2 x^{2} - 26 x = - 3 x^{2} - 7 x - 18

Switch sides

- 3 x^{2} - 7 x - 18 = 2 x^{2} - 26 x

Move

26 x

to the left side

- 3 x^{2} + 19 x - 18 = 2 x^{2}

Move

2 x^{2}

to the left side

- 5 x^{2} + 19 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 ( - 5 ) ( - 18 )}{2 ( - 5 )}

1 9^{2} - 4 (- 5) (- 18) = 1

x_{1, 2} = \frac{- 19 \pm 1}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 19 + 1}{2 ( - 5 )}, x_{2} = \frac{- 19 - 1}{2 ( - 5 )}

x = \frac{- 19 + 1}{2 ( - 5 )} : \frac{9}{5}

x = \frac{- 19 - 1}{2 ( - 5 )} : 2

The solutions to the quadratic equation are:

x = \frac{9}{5}, x = 2

(6 x - 3) (- x + 3) = 0

0 = 4 + 23.5 t - 4.9 t^{2}

3 y^{2} - 4 y = 2 y + 7 y

- 33.2 x^{2} - 2.66 x + 0.04 = 0

y, 2 x^{2} + 3 y^{2} - 8 x + 6 y + 14 = 0

What are the solutions to the equation 2x^2-26x=-3x^2-7x-18 ?
The solutions to the equation 2x^2-26x=-3x^2-7x-18 are x= 9/5 ,x=2
Find the zeros of 2x^2-26x=-3x^2-7x-18
The zeros of 2x^2-26x=-3x^2-7x-18 are x= 9/5 ,x=2