What is the answer to solvefor F,gb+Nb=2F(b)^2 ?

The answer to solvefor F,gb+Nb=2F(b)^2 is F=(g+N)/(2b);\quad b\ne 0

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solvefor F,gb+Nb=2F(b)^2

solve for

F, g b + N b = 2 F (b)^{2}

F = \frac{g + N}{2 b}; b \neq = 0

Solution steps

g b + N b = 2 F b^{2}

Switch sides

2 F b^{2} = g b + N b

Divide both sides by

2 b^{2}; b \neq = 0

F = \frac{g + N}{2 b}; b \neq = 0

10 x^{2} = 16 x + 6 x^{2}

x^{2} - 6 x + 15 = - (x - 3)^{2} + 6

- 5 x^{2} + 4 x - 6 = 0

x, x^{2} + y^{2} + z^{2} = 4 z

x^{2} - 2 x + 1 = 0

What is the answer to solvefor F,gb+Nb=2F(b)^2 ?
The answer to solvefor F,gb+Nb=2F(b)^2 is F=(g+N)/(2b);\quad b\ne 0