What are the solutions to the equation 25x^2+40x-9=0 ?

The solutions to the equation 25x^2+40x-9=0 are x= 1/5 ,x=-9/5

Find the zeros of 25x^2+40x-9=0

The zeros of 25x^2+40x-9=0 are x= 1/5 ,x=-9/5

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25 x^{2} + 40 x - 9 = 0

x = \frac{1}{5}, x = - \frac{9}{5}

Decimal

x = 0.2, x = - 1.8

Solution steps

25 x^{2} + 40 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 25 ( - 9 )}{2 \cdot 25}

4 0^{2} - 4 \cdot 25 (- 9) = 50

x_{1, 2} = \frac{- 40 \pm 50}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 40 + 50}{2 \cdot 25}, x_{2} = \frac{- 40 - 50}{2 \cdot 25}

x = \frac{- 40 + 50}{2 \cdot 25} : \frac{1}{5}

x = \frac{- 40 - 50}{2 \cdot 25} : - \frac{9}{5}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - \frac{9}{5}

x^{2} - 36 = 12 x

4 + 2 (5 x + 2 x^{2}) = 11

x^{2} - 2 x - 3 = 0

2 x^{2} + 3 x - 2 = 0

x^{2} - 5 x = 8

What are the solutions to the equation 25x^2+40x-9=0 ?
The solutions to the equation 25x^2+40x-9=0 are x= 1/5 ,x=-9/5
Find the zeros of 25x^2+40x-9=0
The zeros of 25x^2+40x-9=0 are x= 1/5 ,x=-9/5