What are the solutions to the equation solvefor t,6(2t-1)^2=0 ?

The solutions to the equation solvefor t,6(2t-1)^2=0 are t= 1/2

Find the zeros of solvefor t,6(2t-1)^2=0

The zeros of solvefor t,6(2t-1)^2=0 are t= 1/2

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solve for

t, 6 (2 t - 1)^{2} = 0

t = \frac{1}{2}

Decimal

t = 0.5

Solution steps

6 (2 t - 1)^{2} = 0

Divide both sides by

6

(2 t - 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

2 t - 1 = 0 : t = \frac{1}{2}

The solution to the quadratic equation is:

t = \frac{1}{2}

4 (x + 6) + 4 x = x (x + 6)

x^{2} - 2 x = 0

2 y^{2} - y - 2 = 0

x^{2} - 58 = - 9

16 (x^{2} - 2) + 19 = 12

What are the solutions to the equation solvefor t,6(2t-1)^2=0 ?
The solutions to the equation solvefor t,6(2t-1)^2=0 are t= 1/2
Find the zeros of solvefor t,6(2t-1)^2=0
The zeros of solvefor t,6(2t-1)^2=0 are t= 1/2