What are the solutions to the equation roots x^2-x-3 ?

The solutions to the equation roots x^2-x-3 are x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2

Find the zeros of roots x^2-x-3

The zeros of roots x^2-x-3 are x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2

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roots

x^{2} - x - 3

x = \frac{1 + 13}{2}, x = \frac{1 - 13}{2}

Solution steps

x^{2} - x - 3

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 3) = 13

x_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 1}

x = \frac{- ( - 1 ) + 13}{2 \cdot 1} : \frac{1 + 13}{2}

x = \frac{- ( - 1 ) - 13}{2 \cdot 1} : \frac{1 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 13}{2}, x = \frac{1 - 13}{2}

\frac{2 x ^{2}}{5} = 90

6 x^{2} + 31 x + 18 = 0

25 = x^{2} + (x + 1)^{2}

9 x^{2} + 5 = 6

- 2 x^{2} - 7 x + 13 = 0

What are the solutions to the equation roots x^2-x-3 ?
The solutions to the equation roots x^2-x-3 are x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2
Find the zeros of roots x^2-x-3
The zeros of roots x^2-x-3 are x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2