What are the solutions to the equation z^2+10z-24=0 ?

The solutions to the equation z^2+10z-24=0 are z=2,z=-12

Find the zeros of z^2+10z-24=0

The zeros of z^2+10z-24=0 are z=2,z=-12

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z^{2} + 10 z - 24 = 0

z = 2, z = - 12

Solution steps

z^{2} + 10 z - 24 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 24) = 14

z_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 10 + 14}{2 \cdot 1}, z_{2} = \frac{- 10 - 14}{2 \cdot 1}

z = \frac{- 10 + 14}{2 \cdot 1} : 2

z = \frac{- 10 - 14}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

z = 2, z = - 12

4 (9 + 5 x^{2}) = 356

3 v^{2} - 75 = 0

26 n^{2} + 41 n + 20 = 6 n^{2}

3 x^{2} = - 147

2 x^{2} - 9 x = x^{2}

What are the solutions to the equation z^2+10z-24=0 ?
The solutions to the equation z^2+10z-24=0 are z=2,z=-12
Find the zeros of z^2+10z-24=0
The zeros of z^2+10z-24=0 are z=2,z=-12