What are the solutions to the equation x^2-15=1 ?

The solutions to the equation x^2-15=1 are x=4,x=-4

Find the zeros of x^2-15=1

The zeros of x^2-15=1 are x=4,x=-4

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x^{2} - 15 = 1

x = 4, x = - 4

Solution steps

x^{2} - 15 = 1

Move

15

to the right side

x^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 16, x = - 16

16 = 4

- 16 = - 4

x = 4, x = - 4

x^{2} - 2 π x - 3 π^{2} = 0

12 x^{2} + 48 = 0

h^{2} - 3 h - 28 = 0

(x + 5)^{2} + (x + 3)^{2} = (2 x + 4)^{2}

4 x^{2} + 19 x + 12 = - 5

What are the solutions to the equation x^2-15=1 ?
The solutions to the equation x^2-15=1 are x=4,x=-4
Find the zeros of x^2-15=1
The zeros of x^2-15=1 are x=4,x=-4