What are the solutions to the equation 16x^2+72x+83=0 ?

The solutions to the equation 16x^2+72x+83=0 are x=-9/4+i(sqrt(2))/4 ,x=-9/4-i(sqrt(2))/4

Find the zeros of 16x^2+72x+83=0

The zeros of 16x^2+72x+83=0 are x=-9/4+i(sqrt(2))/4 ,x=-9/4-i(sqrt(2))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16 x^{2} + 72 x + 83 = 0

x = - \frac{9}{4} + i \frac{2}{4}, x = - \frac{9}{4} - i \frac{2}{4}

Solution steps

16 x^{2} + 72 x + 83 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 72 \pm 7 2 ^{2} - 4 \cdot 16 \cdot 83}{2 \cdot 16}

Simplify

7 2^{2} - 4 \cdot 16 \cdot 83 : 82 i

x_{1, 2} = \frac{- 72 \pm 8 2 i}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- 72 + 8 2 i}{2 \cdot 16}, x_{2} = \frac{- 72 - 8 2 i}{2 \cdot 16}

x = \frac{- 72 + 8 2 i}{2 \cdot 16} : - \frac{9}{4} + i \frac{2}{4}

x = \frac{- 72 - 8 2 i}{2 \cdot 16} : - \frac{9}{4} - i \frac{2}{4}

The solutions to the quadratic equation are:

x = - \frac{9}{4} + i \frac{2}{4}, x = - \frac{9}{4} - i \frac{2}{4}

k^{2} + 5 k - 3 = 0

x^{2} + 8 x + 15

3 (3 x + 5)^{2} + 10 = 22

5 x^{2} + 5 x - 9 = 0

(5 x + 6)^{2} + 24 = 33

What are the solutions to the equation 16x^2+72x+83=0 ?
The solutions to the equation 16x^2+72x+83=0 are x=-9/4+i(sqrt(2))/4 ,x=-9/4-i(sqrt(2))/4
Find the zeros of 16x^2+72x+83=0
The zeros of 16x^2+72x+83=0 are x=-9/4+i(sqrt(2))/4 ,x=-9/4-i(sqrt(2))/4