What are the solutions to the equation solvefor x,16x-x^2=28 ?

The solutions to the equation solvefor x,16x-x^2=28 are x=2,x=14

Find the zeros of solvefor x,16x-x^2=28

The zeros of solvefor x,16x-x^2=28 are x=2,x=14

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x, 16 x - x^{2} = 28

x = 2, x = 14

Solution steps

16 x - x^{2} = 28

Move

28

to the left side

16 x - x^{2} - 28 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 16 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 1 ) ( - 28 )}{2 ( - 1 )}

1 6^{2} - 4 (- 1) (- 28) = 12

x_{1, 2} = \frac{- 16 \pm 12}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 16 + 12}{2 ( - 1 )}, x_{2} = \frac{- 16 - 12}{2 ( - 1 )}

x = \frac{- 16 + 12}{2 ( - 1 )} : 2

x = \frac{- 16 - 12}{2 ( - 1 )} : 14

The solutions to the quadratic equation are:

x = 2, x = 14

x^{2} + 62 = 16 x

130 x^{2} - 36 x - 45 = 0

x^{2} + x - 30 = 0

x^{2} - 24 x + 114 = 19

(3 x + 6)^{2} - 43 = - 34

What are the solutions to the equation solvefor x,16x-x^2=28 ?
The solutions to the equation solvefor x,16x-x^2=28 are x=2,x=14
Find the zeros of solvefor x,16x-x^2=28
The zeros of solvefor x,16x-x^2=28 are x=2,x=14