What are the solutions to the equation 3z^2-7z+3=6 ?

The solutions to the equation 3z^2-7z+3=6 are z=(7+sqrt(85))/6 ,z=(7-sqrt(85))/6

Find the zeros of 3z^2-7z+3=6

The zeros of 3z^2-7z+3=6 are z=(7+sqrt(85))/6 ,z=(7-sqrt(85))/6

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3 z^{2} - 7 z + 3 = 6

z = \frac{7 + 85}{6}, z = \frac{7 - 85}{6}

Decimal

z = 2.70325 \dots, z = - 0.36992 \dots

Solution steps

3 z^{2} - 7 z + 3 = 6

Move

6

to the left side

3 z^{2} - 7 z - 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 3) = 85

z_{1, 2} = \frac{- ( - 7 ) \pm 85}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- ( - 7 ) + 85}{2 \cdot 3}, z_{2} = \frac{- ( - 7 ) - 85}{2 \cdot 3}

z = \frac{- ( - 7 ) + 85}{2 \cdot 3} : \frac{7 + 85}{6}

z = \frac{- ( - 7 ) - 85}{2 \cdot 3} : \frac{7 - 85}{6}

The solutions to the quadratic equation are:

z = \frac{7 + 85}{6}, z = \frac{7 - 85}{6}

(- 4 - x) (1 - x) + 6 = 0

9 v^{2} = - 30 v - 25

5 m^{2} + 7 = 52

54 = 6 + 6 a^{2}

r^{2} + 4 r + 5

What are the solutions to the equation 3z^2-7z+3=6 ?
The solutions to the equation 3z^2-7z+3=6 are z=(7+sqrt(85))/6 ,z=(7-sqrt(85))/6
Find the zeros of 3z^2-7z+3=6
The zeros of 3z^2-7z+3=6 are z=(7+sqrt(85))/6 ,z=(7-sqrt(85))/6