What are the solutions to the equation roots r^2+4r+5 ?

The solutions to the equation roots r^2+4r+5 are r=-2+i,r=-2-i

Find the zeros of roots r^2+4r+5

The zeros of roots r^2+4r+5 are r=-2+i,r=-2-i

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roots

r^{2} + 4 r + 5

r = - 2 + i, r = - 2 - i

Solution steps

r^{2} + 4 r + 5

The roots are the intercepts with the x-axis

(y = 0)

r^{2} + 4 r + 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 5 : 2 i

r_{1, 2} = \frac{- 4 \pm 2 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 4 + 2 i}{2 \cdot 1}, r_{2} = \frac{- 4 - 2 i}{2 \cdot 1}

r = \frac{- 4 + 2 i}{2 \cdot 1} : - 2 + i

r = \frac{- 4 - 2 i}{2 \cdot 1} : - 2 - i

The solutions to the quadratic equation are:

r = - 2 + i, r = - 2 - i

x^{2} + \frac{9}{2} x + \frac{7}{2} = 0

2 x^{2} + 15 x - 7 = 2 x

- 3 x^{2} + 11 = 95

x^{2} + 31 = - 12 x

2 x^{2} + 16 x + 26

What are the solutions to the equation roots r^2+4r+5 ?
The solutions to the equation roots r^2+4r+5 are r=-2+i,r=-2-i
Find the zeros of roots r^2+4r+5
The zeros of roots r^2+4r+5 are r=-2+i,r=-2-i