What are the solutions to the equation z^2+12z=-11 ?

The solutions to the equation z^2+12z=-11 are z=-1,z=-11

Find the zeros of z^2+12z=-11

The zeros of z^2+12z=-11 are z=-1,z=-11

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z^{2} + 12 z = - 11

z = - 1, z = - 11

Solution steps

z^{2} + 12 z = - 11

Move

11

to the left side

z^{2} + 12 z + 11 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 11}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 11 = 10

z_{1, 2} = \frac{- 12 \pm 10}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 12 + 10}{2 \cdot 1}, z_{2} = \frac{- 12 - 10}{2 \cdot 1}

z = \frac{- 12 + 10}{2 \cdot 1} : - 1

z = \frac{- 12 - 10}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

z = - 1, z = - 11

r^{2} + 22 r + 2 = 0

10 x^{2} - 148 x + 490 = 0

3 x^{2} - 240 = 0

4 x^{2} + 21 = 4 x

y, x^{2} + y^{2} - 8 x + 6 y + 29 = 0

What are the solutions to the equation z^2+12z=-11 ?
The solutions to the equation z^2+12z=-11 are z=-1,z=-11
Find the zeros of z^2+12z=-11
The zeros of z^2+12z=-11 are z=-1,z=-11