What are the solutions to the equation 10x^2-7x-1=0 ?

The solutions to the equation 10x^2-7x-1=0 are x=(7+sqrt(89))/(20),x=(7-sqrt(89))/(20)

Find the zeros of 10x^2-7x-1=0

The zeros of 10x^2-7x-1=0 are x=(7+sqrt(89))/(20),x=(7-sqrt(89))/(20)

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10 x^{2} - 7 x - 1 = 0

x = \frac{7 + 89}{20}, x = \frac{7 - 89}{20}

Decimal

x = 0.82169 \dots, x = - 0.12169 \dots

Solution steps

10 x^{2} - 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 10 ( - 1 )}{2 \cdot 10}

(- 7)^{2} - 4 \cdot 10 (- 1) = 89

x_{1, 2} = \frac{- ( - 7 ) \pm 89}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 89}{2 \cdot 10}, x_{2} = \frac{- ( - 7 ) - 89}{2 \cdot 10}

x = \frac{- ( - 7 ) + 89}{2 \cdot 10} : \frac{7 + 89}{20}

x = \frac{- ( - 7 ) - 89}{2 \cdot 10} : \frac{7 - 89}{20}

The solutions to the quadratic equation are:

x = \frac{7 + 89}{20}, x = \frac{7 - 89}{20}

7 x^{2} + 28 x + 30 = 0

0 = x^{2} + 8 x + 5

x^{2} + 58 = 9

x^{2} - 14 x + 62 = - 77

25 (1 - 4 x)^{2} - 28 = - 12

What are the solutions to the equation 10x^2-7x-1=0 ?
The solutions to the equation 10x^2-7x-1=0 are x=(7+sqrt(89))/(20),x=(7-sqrt(89))/(20)
Find the zeros of 10x^2-7x-1=0
The zeros of 10x^2-7x-1=0 are x=(7+sqrt(89))/(20),x=(7-sqrt(89))/(20)