What are the solutions to the equation roots s^2+s+100 ?

The solutions to the equation roots s^2+s+100 are s=-1/2+i(sqrt(399))/2 ,s=-1/2-i(sqrt(399))/2

Find the zeros of roots s^2+s+100

The zeros of roots s^2+s+100 are s=-1/2+i(sqrt(399))/2 ,s=-1/2-i(sqrt(399))/2

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roots

s^{2} + s + 100

s = - \frac{1}{2} + i \frac{399}{2}, s = - \frac{1}{2} - i \frac{399}{2}

Solution steps

s^{2} + s + 100

The roots are the intercepts with the x-axis

(y = 0)

s^{2} + s + 100 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 100 : 399 i

s_{1, 2} = \frac{- 1 \pm 399 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 1 + 399 i}{2 \cdot 1}, s_{2} = \frac{- 1 - 399 i}{2 \cdot 1}

s = \frac{- 1 + 399 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{399}{2}

s = \frac{- 1 - 399 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{399}{2}

The solutions to the quadratic equation are:

s = - \frac{1}{2} + i \frac{399}{2}, s = - \frac{1}{2} - i \frac{399}{2}

(x + 10) (- x - 8) = 0

2 x^{2} - 2 x - 12 = 0

4 x^{2} - 15 x + 12 = 0

y, 3 x^{2} - 6 x y + y^{2} = 2 x - y

r^{2} - r + 9 = 0

What are the solutions to the equation roots s^2+s+100 ?
The solutions to the equation roots s^2+s+100 are s=-1/2+i(sqrt(399))/2 ,s=-1/2-i(sqrt(399))/2
Find the zeros of roots s^2+s+100
The zeros of roots s^2+s+100 are s=-1/2+i(sqrt(399))/2 ,s=-1/2-i(sqrt(399))/2