What are the solutions to the equation solvefor y,x^2y^2=3x ?

The solutions to the equation solvefor y,x^2y^2=3x are y=sqrt(3/x),y=-sqrt(3/x);\quad x\ne 0

Find the zeros of solvefor y,x^2y^2=3x

The zeros of solvefor y,x^2y^2=3x are y=sqrt(3/x),y=-sqrt(3/x);\quad x\ne 0

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solve for

y, x^{2} y^{2} = 3 x

y = \frac{3}{x}, y = - \frac{3}{x}; x \neq = 0

Solution steps

x^{2} y^{2} = 3 x

Divide both sides by

x^{2}; x \neq = 0

y^{2} = \frac{3}{x}; x \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{3}{x}, y = - \frac{3}{x}; x \neq = 0

x^{2} - 40 = - 6 x

\frac{3}{2} y^{2} - 6 y = \frac{3}{4} y - 9

36 = x^{2} + x^{2}

y, x^{2} + x y - 2 y^{2} = 0

\frac{w ^{2}}{6} - \frac{w}{3} - 4 = 0

What are the solutions to the equation solvefor y,x^2y^2=3x ?
The solutions to the equation solvefor y,x^2y^2=3x are y=sqrt(3/x),y=-sqrt(3/x);\quad x\ne 0
Find the zeros of solvefor y,x^2y^2=3x
The zeros of solvefor y,x^2y^2=3x are y=sqrt(3/x),y=-sqrt(3/x);\quad x\ne 0